Tue, 01 Sep 2015 18:28:11 +0530
8068901: Surprising behavior with more than one functional interface on a class
8068903: Can't invoke vararg @FunctionalInterface methods
Reviewed-by: attila, hannesw
1 /*
2 * Copyright (c) 2010, 2013, Oracle and/or its affiliates. All rights reserved.
3 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
4 *
5 * This code is free software; you can redistribute it and/or modify it
6 * under the terms of the GNU General Public License version 2 only, as
7 * published by the Free Software Foundation.
8 *
9 * This code is distributed in the hope that it will be useful, but WITHOUT
10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
12 * version 2 for more details (a copy is included in the LICENSE file that
13 * accompanied this code).
14 *
15 * You should have received a copy of the GNU General Public License version
16 * 2 along with this work; if not, write to the Free Software Foundation,
17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
18 *
19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
20 * or visit www.oracle.com if you need additional information or have any
21 * questions.
22 */
24 /**
25 * typeof second round.
26 *
27 * @test
28 * @run
29 */
31 var o = {a: 10, b: 20, c: 30};
32 var p = "string";
34 print(typeof undefined);
35 print(typeof true);
36 print(typeof 10.0);
37 print(typeof "string");
38 print(typeof o);
39 print(typeof [1, 2, 3]);
40 print(typeof o.a);
41 print(typeof p);
42 print(typeof o.d);
43 print(typeof o["d"]);
44 print(typeof this["q"]);
45 print(typeof this.q);