Tue, 01 Sep 2015 18:28:11 +0530
8068901: Surprising behavior with more than one functional interface on a class
8068903: Can't invoke vararg @FunctionalInterface methods
Reviewed-by: attila, hannesw
1 /*
2 * Copyright (c) 2010, 2013, Oracle and/or its affiliates. All rights reserved.
3 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
4 *
5 * This code is free software; you can redistribute it and/or modify it
6 * under the terms of the GNU General Public License version 2 only, as
7 * published by the Free Software Foundation.
8 *
9 * This code is distributed in the hope that it will be useful, but WITHOUT
10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
12 * version 2 for more details (a copy is included in the LICENSE file that
13 * accompanied this code).
14 *
15 * You should have received a copy of the GNU General Public License version
16 * 2 along with this work; if not, write to the Free Software Foundation,
17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
18 *
19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
20 * or visit www.oracle.com if you need additional information or have any
21 * questions.
22 */
24 /**
25 * new Function test.
26 *
27 * @test
28 * @run
29 */
31 function MyObject() {
32 this.x = 10;
33 this.y = "string";
34 this.z = function() {
35 return true;
36 }
37 };
39 var a = new MyObject();
41 print(a.x);
42 print(a.y);
43 print(a.z);
45 var b = new MyObject;
47 print(b.x);
48 print(b.y);
49 print(b.z);
51 var obj = {
52 func: function() {
53 print("obj.func called");
54 }
55 };
57 var x = new obj.func;
58 print(x);
60 x = new function f1(){ print("in f1"); return 1;};
61 print(typeof(x));