Tue, 01 Sep 2015 18:28:11 +0530
8068901: Surprising behavior with more than one functional interface on a class
8068903: Can't invoke vararg @FunctionalInterface methods
Reviewed-by: attila, hannesw
1 Enumerable items in Array.prototype = 0
2 Enumerable items in Array = 0
3 Enumerable items in Boolean.prototype = 0
4 Enumerable items in Boolean = 0
5 Enumerable items in Date.prototype = 0
6 Enumerable items in Date = 0
7 Enumerable items in Function.prototype = 0
8 Enumerable items in Function = 0
9 Enumerable items in JSON = 0
10 Enumerable items in Math = 0
11 Enumerable items in Number.prototype = 0
12 Enumerable items in Number = 0
13 Enumerable items in Object.prototype = 0
14 Enumerable items in Object = 0
15 Enumerable items in String.prototype = 0
16 Enumerable items in String = 0