Tue, 01 Sep 2015 18:28:11 +0530
8068901: Surprising behavior with more than one functional interface on a class
8068903: Can't invoke vararg @FunctionalInterface methods
Reviewed-by: attila, hannesw
1 /*
2 * Copyright (c) 2010, 2013, Oracle and/or its affiliates. All rights reserved.
3 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
4 *
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7 * published by the Free Software Foundation.
8 *
9 * This code is distributed in the hope that it will be useful, but WITHOUT
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12 * version 2 for more details (a copy is included in the LICENSE file that
13 * accompanied this code).
14 *
15 * You should have received a copy of the GNU General Public License version
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22 */
24 /**
25 * JDK-8015345: Function("}),print('test'),({") should throw SyntaxError
26 *
27 * @test
28 * @run
29 */
31 function checkFunction(code) {
32 try {
33 Function(code);
34 fail("should have thrown SyntaxError for :" + code);
35 } catch (e) {
36 if (! (e instanceof SyntaxError)) {
37 fail("SyntaxError expected, but got " + e);
38 }
39 print(e);
40 }
41 }
43 // invalid body
44 checkFunction("}),print('test'),({");
46 // invalid param list
47 checkFunction("x**y", "print('x')");
49 // invalid param identifier
50 checkFunction("in", "print('hello')");
51 //checkFunction("<>", "print('hello')")
53 // invalid param list and body
54 checkFunction("x--y", ")");
56 // check few valid cases as well
57 var f = Function("x", "return x*x");
58 print(f(10))
60 f = Function("x", "y", "return x+y");
61 print(f(33, 22));
63 f = Function("x,y", "return x/y");
64 print(f(24, 2));